Calculate the Fermi energy, EF at 0K for potassium (atomic weight = 39, density = 860 kgm3).
KF3 = 3π2n
Fermi Momentum ρ = h(bar)KF
The Attempt at a Solution:[/B]
For the first part:
Using: E = ρ2/ 2m
Can substitute Fermi momentum into that to get:
EF = h(bar)2 KF2 / 2m
KF2 = √(3π2n) = π√(3n)
Putting all the together I got:
EF = h(bar)2 π √(3n) / 2m
which is the same as: EF = h2 √(3n) / 4m
I'm not too sure what to do after this point as I'm not sure how the atomic weight or density can give me a value for n and m. I do have written in my notes that n = N/v but again I wasn't sure how this would help me. I feel like I must be going down the wrong path to come out with an equation that needs completely different things to what the question is providing me with. But honestly I have just started this condensed matter course and haven't really got my feet yet.
Thanks in advance to anyone that replies.