Calculating the Force Constant of a Spring

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To find the force constant of a spring using a Newton meter, plot the force applied on the Y-axis against the displacement on the X-axis; the slope of this graph will yield the spring constant (k). The formula k = F/d can be used for calculations. For determining the stretch needed for a spring in a projectile scenario, the equation ½mv²=½kx² can be utilized to find velocity, followed by using d=[v²sin2(theta)]/g for horizontal distance. The combined equation for range is Range = (kx² sin 2θ)/mg, which is considered the most straightforward approach. Understanding these concepts is crucial for accurate calculations in physics problems involving springs and projectile motion.
marshall4
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How do i find the force constant of a spring with a Newton meter?
Do i graph the force applied vs. distance of stretch? What is on the x-axis, what is on the y-axis?

How do i find an equation for the amount of skretch needed for on spring on a projectile, with the horizontal distance, angle of the projectile, mass and force constant given?
 
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What kind of textbook are you using in your school?
 
Originally posted by marshall4
How do i find the force constant of a spring with a Newton meter?
Do i graph the force applied vs. distance of stretch? What is on the x-axis, what is on the y-axis?
F = kd
k = F/d
Now that you know the formula, it's easy to figure it out. Plot force on the Y axis and displacement on the x axis. The slope of the graph will give you the k value.


Your second question is difficult to understand. Can you reword it or say it differently?
 
Originally posted by PiRsq
What kind of textbook are you using in your school?

Nelson Physics 12
Why?
 


Originally posted by ShawnD



Your second question is difficult to understand. Can you reword it or say it differently?

I'm launching a spring off the end of an angled launch pad (projectile) at angle Өtheta, i want to find how long i have to skretch the spring in order for the spring to go x metres in the horizontal distance.

i think i use the equation ½mv²=½kx² to find the velocity. Then I use that velocity in the equation d=[v²sin2(theta)]/g, to find the horizontal distance. Does that sound right, or is there an easier equation?
 
Last edited:
Combine the equations to get the result

Range = (kx2 sin 2θ)/mg

I can't see it getting any easier.
 
Checkout Sample Problem #4 on pg 209
 

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