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## Homework Statement

Let the DTFT (Discrete time Fourier transform) of a signal be

Y(f)=

{1 0≤lfl< [itex]\frac{fs}{8}[/itex]

{0 Otherwise

Calc y(k)

## Homework Equations

[itex]

y(k)=\frac{1}{f_{s}}[/itex][itex]\int Y(f) e^{jk2\pi fT}df lkl≥0 [/itex]

## The Attempt at a Solution

So what I understand from this is that my Y(f) is basically 1 when f is between the boundaries of 0 and [itex]\frac{f_{s}}{8}[/itex]

So I basically get just the exponential in my inverse formula right?

So [itex] y(k)= \frac{1}{f_{s}}\int e^{jk2/pi ft}

[/itex]

Which leads to be

[itex]

\frac{1}{f_{s}} e^{jk2 \pi ft}

[/itex]

However i feel this is incorrect as I dont know what to really do with my limit of fs/8?

Thanks for any hlep..