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Introductory Physics Homework Help
Calculating the magnitude of an impulse
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[QUOTE="Nkele, post: 5998908, member: 645647"] [h2]Homework Statement[/h2] Aplayer bounces a 0.43-kg soccer ball off her head, changing the velocity of the ball from Vi = (8.8 m/s)x + (-2.3 m/s)y [B][SIZE=4][FONT=PT Sans][COLOR=rgb(5, 5, 5)] to [B][SIZE=4][FONT=PT Sans][COLOR=rgb(5, 5, 5)]Vf = (5.2 m/s)xN + (3.7 m/s)y[/COLOR][/FONT][/SIZE][/B][/COLOR][/FONT][/SIZE][/B][/B] . If the ball is in contact with the player’s head for 6.7 ms, what are (a) the direction and (b) the magnitude of the impulse delivered to the ball? Will I be wrong if I use just change in velocities(ie excluding) in x-comp and y-comp to calculate direction of the impulse. I did calculation which gave me theta of -59.03, and when using coordinates the theta falls in second quadrant.[B][/B][h2]Homework Equations[/h2] 1. delta P(x comp)= Pf(x)-Pi(x)= -1.548 2. delta P(y comp)=Pf(y)-Pi(y)=2.58[h2]The Attempt at a Solution[/h2] Using the solutions I calculated magnitude of impulse as 3.03 kg.m/s [/QUOTE]
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Introductory Physics Homework Help
Calculating the magnitude of an impulse
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