Calculating the Mass of a Tractor Being Dragged by a Tow Truck on Wet Concrete

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SUMMARY

The discussion centers on calculating the mass of a tractor that can be dragged by a tow truck on wet concrete, given a coefficient of limiting static friction of 0.70 and a horizontal force exerted by the tow truck of 10,000 N. The calculation performed is correct, yielding a maximum mass of approximately 1457.72 kg. It is noted that a tractor with a greater mass could be moved if it were already in motion, due to the lower coefficient of kinetic friction compared to static friction.

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Homework Statement


The coefficient of limiting static friction of a rubber tire in wet concrete is 0.70. What mass of tractor, with its brakes locked, can be dragged by a tow truck that can exert a horizontal force of 1.0 * 10^4 N?


Homework Equations


Fnetx = ma

Ff = us*Fn

Fn = m*g

The Attempt at a Solution


10000 / (0.70*9.8) = 1457.72


Is that right??...Help NEEDED:confused:
 
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What you calculated is the maximum mass of a tractor that can be moved, starting from rest on a horizontal surface, by a tow truck. Because the coeff. of kinetic friction is less than that of static friction, a more massive tractor could be pulled if it started with a nonzero speed. NOTE: I am just nitpicking the question, your solution seems fine to me.
 
oo so thaz rite??
 
yes, good.
 

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