Calculating the mass of matter required to accelerate a spaceship

Click For Summary

Homework Help Overview

The discussion revolves around calculating the mass of matter required to accelerate a spaceship powered by a matter-antimatter reactor to a speed of 0.03 times the speed of light (c). The problem involves concepts from relativistic physics and energy-mass equivalence.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of Einstein's equation E=mc² and question the validity of using F=ma at relativistic speeds. There is an attempt to understand the relationship between kinetic energy and the mass-energy equivalence in the context of the problem.

Discussion Status

Some participants have provided insights into the correct application of relativistic concepts, suggesting a focus on kinetic energy rather than classical mechanics. There is acknowledgment of a misunderstanding regarding kinetic energy and its relation to the problem, leading to further exploration of the topic.

Contextual Notes

Participants are navigating the complexities of relativistic physics and the implications of using classical equations at high velocities. There is also a mention of formatting equations in the forum, indicating a learning aspect related to communication in the discussion.

dylhynes
Messages
2
Reaction score
0

Homework Statement


A spaceship is powered by a matter-antimatter reactor. Suppose you have a 23000-metric-ton spaceship and wish to accelerate it to 0.03 c. What is the total mass of matter and anti matter required, assuming a 100 % efficient engine.

Homework Equations


Really not sure about this question, but thinking that E=mc^2 and F=ma will be used somewhere

The Attempt at a Solution


Not sure how to approach this problem, any help would be greatly appreciated.
 
Physics news on Phys.org
You are right about ## E = mc^2 ##. This gives you the amount of matter/anti-matter one needs to annihilate to obtain energy ## E ##. However, ## F = ma ## is not good - it is only valid for slow motion, and 0.03 c may be too high for it. Instead, consider the relativistic kinetic energy of some mass M moving at 0.03 c.
 
Ahh, I understand what I did wrong now. I overlooked the fact that the spaceship only has kinetic energy while it is travelling. I solved for KE, then plugged that back into E=mc2. Rearranging for m I got the answer of 1.0x104 kg, which was correct. Thank you very much. Also if you don't mind answering, how did you type those equations in that math font ? I am new here.
 
Hit the quote button my message, and see the code for that. While you are there, click the ## \Sigma ## symbol at the top right of the text box, it will have a reference for much more.
 

Similar threads

Replies
10
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
7
Views
4K
  • · Replies 75 ·
3
Replies
75
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K