Calculating the Period of an Earth Satellite

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Homework Help Overview

The original poster attempts to calculate the period of an Earth satellite orbiting at a height of 1.80 x 10^7 m above the Earth's surface, using the gravitational constant and the mass of the Earth. The problem involves understanding orbital mechanics and the application of relevant formulas.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for calculating the period, questioning the values used for the radius and the gravitational constant. There are attempts to clarify the calculations and the units of the final answer.

Discussion Status

Some participants have provided guidance on the calculations and the correct interpretation of the radius. There is an ongoing exploration of the correct method to input scientific notation into calculators, with various suggestions being offered. Multiple interpretations of the calculations are being discussed, but no consensus has been reached.

Contextual Notes

There are indications of confusion regarding the use of scientific notation in calculations, as well as the proper addition of the Earth's radius and the satellite's height. The original poster expresses frustration with their calculator's functionality, which may be affecting their ability to arrive at a solution.

Chica1975
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Homework Statement


What is the period of an Earth satellite orbiting at a height of 1.80 x 10^7m above the surface of the earth? Use G = 6.67 x 10^-11 N.m2 Kg-2


Homework Equations



T = SQRT 4*pi^2 * R^3/G*Mass of the earth

The Attempt at a Solution


I added the Earth mass and the height and got = 5.98 x 10^24
Then I plugged everything into the equation but cannot get the answer out. I am not so great on this scientific notation addition etc calculations on the calculator.

the answer is 10.5 but I can't get it out.

PLEASE HELP!
 
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hello there,

please provide some details about your calculations and about the units of the answer.

It's 10.5 what ? (mention the units)
 
the units in the answer are hours - the answer was given by the lecturer.

I plugged in the formulae as per above and got

sqrt of 39.4784176 * 3.97471 * E33/ 1764366 =38.379 hours
 
Chica1975 said:
above the surface of the earth

It means orbit radius is not 1.80x107.

Edit: I see you posted in the meantime. Numbers you show don't make much sense, please elaborate what they are.
 
yes that is the height I multiplied the radius of the Earth and the height of satellite
 
I meant to say I added not multiplied
 
Chica1975 said:
3.97471E33/ 1764366

Neither of these numbers is correct. I guess first one should be R3 and the other one GM.
 
Borek said:
It means orbit radius is not 1.80x107.

Edit: I see you posted in the meantime. Numbers you show don't make much sense, please elaborate what they are.

I have basically looked at the formula and plugged in what it says. Radius is the radius of Earth (6.38 x 10^6) plus the height of satellite. Then the gravitational constant is given. and pi we know. and then mass of the Earth (5.98x 10^24)
 
Borek is right. Your calculations are actually very strange

As for the radius, it must be the sum of the radius of Earth + the height of the satellite
 
  • #10
then there is no way you can get that crazy E33 number ! u'll get smth around E21
 
  • #11
Chica - please explain how do you enter these numbers into your calculator. Key by key.
 
  • #12
exactly - my calculator is driving me crazy - every time I use E anything it spits out something I cannot fathom I am so over it you have no idea I have doing this for 3 hours now.
 
  • #13
I type it like this for eg the radius of the earth
(6.38 shift e (6)) + (1.80 shift e (7)) and press the equals sign
 
  • #14
radius of the Earth + height of satellite is what I meant - am frazzled! :)
 
  • #15
despite being told not to use the x10^X on my calculator - I tried it with that and I got it out. so much for my tutor being on the ball! Thanks everyone.
 
  • #16
No idea what calculator you use, most of those I know don't require something like "shift e", they have just a separate key for exponents. For example EE on TI calculators, or EXP on old Casio.
 

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