Calculating the Rate of Nuclear Fission with 1000 kW Power and 200 MeV Energy

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Homework Help Overview

The discussion revolves around calculating the rate of nuclear fission in a reactor generating 1000 kW of power, with each fission of U-235 releasing 200 MeV of energy. Participants are exploring the relationship between power, energy per fission, and the rate of fission reactions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are examining the definitions of power and energy per fission, questioning how these can be used to determine the number of fissions per second. There is a focus on expressing energy in consistent units and relating energy to the rate of fission reactions.

Discussion Status

The discussion is active, with participants providing insights into the relationships between the quantities involved. Some are suggesting ways to express energy per fission in terms of the total energy output, while others are questioning how to derive the fission rate from the given power and energy values.

Contextual Notes

Participants are working under the constraints of using specific energy units (MeV) and power (kW), and there is an emphasis on ensuring consistency in units throughout the calculations.

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200 MeV of energy may be obtained per fission of U 235. A reactor is generating 1000 Kw of power. Find the rate of nuclear fission ?
Please help...
 
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You know the power, and you now the energy per fission. What are their definitions? How do you use them to get fission per second?
 
Last edited:
P = dW/dt = 1000000J/s

1 fission = 200 MeV = . . .
 
You know that one fission gives 200 MeV energy. So the amount of energy per fission reaction is 200 MeV per fission reaction. If N is the number of fission reactions, this can be expressed as dE/dN. Now you want to find fission reaction per second, dN/dt.

How do you get dN/dt with dE/dN and dE/dt (power)?
 

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