Calculating the Taylor Series for Arctan(x): Explained and Illustrated

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Homework Help Overview

The discussion revolves around calculating the Taylor series for the arctan(x) function, specifically focusing on a given series that appears to be related to this expansion. Participants are exploring how to apply the Taylor series concept to the series presented.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to connect the given series to the Taylor series for arctan(x) and are questioning how to apply this connection. There is discussion about the convergence of the series and the use of the alternating series test. Some participants express confusion about the problem's requirements, particularly regarding the term "sum the series."

Discussion Status

The discussion is active, with participants providing guidance on convergence tests and exploring the implications of the series' structure. There is recognition that while the alternating series test can indicate convergence, it does not provide definitive conclusions about divergence. Participants are also considering the concept of resummation and how it relates to the Taylor expansion.

Contextual Notes

One participant notes that the problem is from a practice exam and specifically instructs to "sum the following series," which adds a layer of complexity to the discussion regarding interpretation and expectations.

vucollegeguy
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The series is:

(33/5) - (34/7) + (35/9) - (36/11)+...

Looking at this, I'm guessing I can use the Taylor Series for arctan(x) but I don't know how to apply it or where to begin.

Any help is greatly appreciated.
 
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You have 33/5 - 34/7 + 35/9 - 36/11 +...
= 33(1/5 - 3/7 + 32/9 - 33/11 +...)
=~3^3~\sum_{n = 0}^{\infty}(-1)^n~\frac{3^n}{2n + 5}

The series above is an alternating series. Do you know a test for determining whether such a series converges?
 
I can use the alternating series test where I let bn=(3n)/(2n+5), right?
 
The title of your post is "sum the series". I doubt that is what you mean. You probably mean test it for convergence.

Anyway, remember the alternating series test will only tell you a series is convergent. If the test for convergence fails, that does not tell you the series diverges. So the alternating series might not (hint, hint) be the end of the story for this problem.
 
Last edited:
This is what I'm confused about. This is a practice exam for my final. And question specifically says "Sum the following series."

I did what mark44 did and factored out the 3^(3) but I didn't come up with the sum formula. When I factored it out, it looked as if it were from the Taylor Series of arctan(x).

Now, I don't know where to go from here.
 
If you forget about convergence issues and want to "sum" the series in the sense of taking the Taylor expansion of some function and insert some value for x so that the expansion matches your series, then this is an example of a "resummation" method.

The idea is then that the series represents a finite number that was derived formally correctly, but it is an expansion around some point yielding a divergent series. But the terms of the expansion will contain all the information about the number which you have to "decode".

You are on the right track with the arctan function. If you look at two successive terms and forget about the missing terms at the start, what should you take for x?
 

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