Calculating the tension in a rope

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SUMMARY

The discussion focuses on calculating the tension in a rope supporting a heavy sack when a sideways force of 220N is applied, resulting in an inclination of 18 degrees to the vertical. To solve part A, the correct approach involves using trigonometric functions, specifically calculating the vertical and horizontal components of the forces. For part B, the mass of the sack can be determined by analyzing the tension derived from the calculations in part A and applying Newton's second law.

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  • Understanding of trigonometric functions and their applications in physics
  • Knowledge of Free Body Diagrams for visualizing forces
  • Familiarity with Newton's second law of motion
  • Basic algebra for solving equations
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of tension in ropes and force analysis in mechanics.

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Homework Statement



A very heavy sack is hung from a rope and pushed sideways. When the sideways push is 220N the rope supporting the sack is inclined 18 degrees to the vertical.

A) Calculate the tension in the rope
B) Hence find the mass of the stack

Homework Equations





The Attempt at a Solution


I'm really cluesless as to what to do on this question. For part A I figured I would try trig and did 220Sin(18) = 67.98. I have no idea if I did that right though, as for part B I thought it would be either splitting the answer I got for tension into it's components and and using the downward force or it would just be the same as the answer to A.
 
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First off, draw a Free Body Diagram. It will help you visualize all the forces involved. Make sure you include everything you know.

Secondly, notice that the angle is not 18 degrees, but 18 degrees to the vertical. That means is 18 degrees away from being 90 degrees.

If those don't help enough, come back and let us know where you're still stuck at.
 

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