Calculating the theoretical force of repulsion between two magnets

Click For Summary
Calculating the theoretical force of repulsion between two magnets involves considering factors such as distance, relative orientation, and size. The discussion highlights that the formula for this force is complex and not straightforward. A referenced Wikipedia page provides examples of different magnet configurations. Participants clarify the relationship between force and distance, correcting terminology from "inverse exponential" to "inverse square." Understanding these principles is essential for accurate calculations in magnetism.
B-RY
Messages
3
Reaction score
0
Homework Statement
I have been asked to complete a student experiment in which I decided to describe the inverse exponential relationship between the force of repulsion and the distance between two magnets.

I was wondering whether it be possible to calculate the theoretical value for the force at each distance?
Relevant Equations
I found this formula on the internet: F=K((m1m2)/((mu)xr^2))
Any help would be much appreciated! Thanks
 
Physics news on Phys.org
Not only distance but relative NS direction angle and even size of magnet matter. The general formula between the magnets is rather complicated. The formula you referred is force between hypothetical magnet charges as if N and S were separable. https://en.wikipedia.org/wiki/Force_between_magnets shows some examples of various configurations.
 
Thankyou!
 
B-RY said:
the inverse exponential relationship between the force of repulsion and the distance between two magnets.
Inverse exponential!?
Inverse quadratic maybe.
 
haruspex said:
Inverse exponential!?
Inverse quadratic maybe.
Inverse square. My bad.
 
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
View full post »

Similar threads

Force between poles of two magnets
Replies
1
Views
1K
Origin of repulsive force on a magnet approaching conducting ring?
Replies
5
Views
1K
Does levitation distance increase as Fg increase???
Replies
1
Views
946
Calculating the number of electrons given the force of repulsion
Replies
5
Views
4K
(Magnetism) Magnetic pull force on a steel ball
Replies
4
Views
2K
I Magnetism: Same Pole Repulsion & Heteropolar Attraction
Replies
32
Views
3K
Determine the force with which the magnetic field of a coil acts on an infinitesimal cube of iron
Replies
6
Views
1K
Electromagnetism question -- Forces between two current carrying wires
Replies
7
Views
3K
Non-Uniform Magnetic Field Calculations
Replies
9
Views
2K
I Questions related to magnetic shielding separating two like poles
Replies
6
Views
906