High School Calculating the torque needed to rotate a drum

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To calculate the torque needed to rotate a drum, key factors include the drum's weight, radius, and whether it experiences friction or acceleration. In this scenario, with a static load and no friction, the required torque would be zero. However, if the drum is performing work, such as tumbling materials, the torque calculation becomes more complex. The placement of the motor and the orientation of the belt also impact the design considerations. Ultimately, without additional details on these variables, a precise torque calculation cannot be made.
jonas_biermann
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Imagine this: You have a drum with a radius of 12cm, around that drum is a toothed belt which is connected to a motor. The drum weighs 10kg
The motor should be placed under the drum

How would I calculate the amount of torque needed to rotate the drum

I don't have any idea how to calculate this but it would be nice if somebody could answer :)
 
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This question is unanswerable with the information you've provided. It really matters a lot if the rotation is accelerating, and if so what the mass moment of inertia around the axis is, if the drum is doing any work (like if there is maybe stones inside it to be fractured or whatever), if there is friction, etc. etc.
 
Arjan82 said:
This question is unanswerable with the information you've provided. It really matters a lot if the rotation is accelerating, and if so what the mass moment of inertia around the axis is, if the drum is doing any work (like if there is maybe stones inside it to be fractured or whatever), if there is friction, etc. etc.
The accelaration is static. There are plants in the drum but the center of mass is in the middle of the drum. For my example friction can be neglected.
 
If there is no friction and no acceleration, and the drum does no other type of work, then the torque is zero
 
jonas_biermann said:
around that drum is a toothed belt which is connected to a motor. The drum weighs 10kg
The motor should be placed under the drum
How can the motor be under the drum if there is a horizontal belt connecting them? Or are they both horizontal and the belt is vertical, and you are tumbling something inside the drum?
jonas_biermann said:
For my example friction can be neglected.
What about the motor bearing friction, and the losses in the belt drive?
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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