The discussion focuses on calculating the torque exerted by an athlete's arm while holding a 2.2 kg steel ball. The arm's length is 74 cm, and its mass is 4.0 kg. The torque is calculated using the formula t = rf, where 'r' is the distance from the shoulder to the point of force application, and 'f' is the force due to gravity. The correct approach involves using the sine function for angles when calculating torque in non-horizontal positions, leading to a final torque calculation of approximately 30.46 N·m for the first position and a corrected value for the second position after applying the cosine function.
PREREQUISITESThis discussion is beneficial for physics students, athletes interested in biomechanics, and anyone studying the mechanics of human movement in sports.
Jaklynn429 said:Homework Statement
An athlete at the gym holds a 2.2 kg steel ball in his hand. His arm is 74 cm long and has a mass of 4.0 kg. What is the magnitude of the torque about his shoulder if he holds his arm in each of the following ways?
1) Parallel out to his side
2) Straight but 35 M below the horizontalHomework Equations
t=rfThe Attempt at a Solution
I don't even know how to start this one :(
Jaklynn429 said:I got the first part by using
(4*.37) + (2.2*.74) = 3.108*9.8=30.46
Now I am having trouble with the second part, wouldn't I just use that answer times sin(35)? I get 17.468 and its telling me I am wrong.