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Calculating total Coulomb force vector ?
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[QUOTE="rude man, post: 6054682, member: 350494"] Your basic approach is OK. It's convenient in this forum to use bold letters to convey vectors. So r_hat = [B]r[/B], i_hat =[B] i[/B], j_hat = [B]j[/B], [B]r[/B] =r cosθ[B] i[/B] + r sinθ [B]j[/B] and [B]F[/B] = F[SUB]x[/SUB] [B]i[/B] + F[SUB]y[/SUB] [B]j[/B]. When you introduce [B]r[/B] you are doing coordinate system switching between cartesian (x,y) and polar (r,θ) coordinates. But this is not necessary. You can just stick with cartesian. So for example [B]F[/B][SUB]2[/SUB] = kq/d[SUP]2[/SUP] [B]i[/B] + kq/d[SUP]2[/SUP] [B]j [/B]and so on for F[SUB]1[/SUB] and F[SUB]3[/SUB]. Then just add all the x and y components separately to get the net force in the[B] i[/B] and [B]j [/B]directions. Note that you don't calculate r[SUP]2[/SUP] =2d[SUP]2[/SUP]separately. [I]At the end[/I] you can still compute [B]r[/B] (and [B]θ)[/B] if you want. [/QUOTE]
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Calculating total Coulomb force vector ?
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