Calculating Total Energy and Vertical Height of Rolling Sphere on Incline

[kbyws37]

A solid sphere of mass 0.599 kg rolls without slipping along a horizontal surface with a translational speed of 5.07 m/s. It comes to an incline that makes an angle of 37.0° with the horizontal surface.

(a) What is the total energy of the rolling sphere? Neglect energy losses due to friction.
(b) To what vertical height above the horizontal surface does the sphere rise on the incline?


To find the total energy of a rolling sphere...
(1/2)mv^2 + (1/5)mv^2
but how would i incorporate 37 degrees?

 

[OlderDan]

but how would i incorporate 37 degrees?

Maybe you don't have to

 

[QuantumCrash]

It only makes a difference if you have to take friction into account.

 

[radou]

You'll need the angle in (b).

 

[OlderDan]

You'll need the angle in (b).

Can you convince me?

 

[QuantumCrash]

It is not necessary for the 'vertical' height. Unless you take into account other forces which makes it more complicated. But then, it does matter.

 

[radou]

Can you convince me?

Actually, by thinking over, I can't.

Apologies, I hope I didn't cause confusion.