Calculating Total Moles of Ions from CuSO4*5H2O

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SUMMARY

The discussion focuses on calculating the total moles of ions released from dissolving 2.63 g of CuSO4*5H2O in water. The correct molar mass of the hydrate is 249.68 g/mol, which includes the water of hydration. The user initially calculated the moles of CuSO4 incorrectly by using the anhydrous molar mass. The final correct answer is 0.0211 moles of ions, accounting for the dissociation into Cu2+ and SO42- ions.

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Homework Statement



How many total moles of ions are released when the following sample dissolves completely in water?

2.63 g of CuSO4 * 5H2O

Homework Equations



159.611 g / mol of CuSO4

The Attempt at a Solution



I tried doing 2.63 g / [159.611 g / mol] to get .016477 mol of CuSO4. and since there are two ions, Cu2+ and SO42- I just multipled the answer by two and got .032955 mol ions

But that isn't the answer. Am I missing anyhting?
 
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Yes, molar mass of hydrate is not that of anhydrous part.

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THANKS! That solved my problem. For reference: the answer is .0211 mol ions
 

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