1. The problem statement, all variables and given/known data Calculate the primary current, and hence the voltage at the transformer input winding, V1. Transformation ratio, a = N1/N2 = 0.1 R1 = 0.12 Ω; R2 = 12 Ω X1 = 0.4 Ω ; X2 = 40 Ω RC = 560 Ω V2 = 2300 V RL = 1 kΩ 'Xm = 800 Ω' 2. Relevant equations R1eq = R1 + a2R2 X1eq = j(X1 + a2X2) V2' = aV2 Current divider equation. 3. The attempt at a solution Approximate equivalent circuit: R1eq = 0.12 + (0.1)2(12) R1eq = 0.24 Ω X1eq = j(0.4 + (0.1)2(40)) X1eq =j0.8 Ω V2' = 0.1(2300) V2' = 230 V a2ZL = (0.1)2(1000) a2ZL = 10 Ω Ip = V2'/a2ZL Ip = 23 A From here is where I believed that there is likely a more efficient way to solve the problem -- particularly because the value of Xm was not actually given in the paper, but told to us during the tutorial, more-or-less made up on the spot. Here is the outline of the given solution: Ip= I1*Z2/(Z1+Z2) ⇒I1 = Ip*(Z1+Z2)/Z2 ⇒I1 = 23*(Rc // Xm + X1eq + R1eq + a2ZL)/ (Rc // Xm) I0 = I1 - Ip ∴ V1 = I0(Rc // Xm) I'd be thankful for any input.