Calculating unknown forces using the principle of moments.

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To calculate the weight of a uniform metre ruler balanced on a knife edge at the 350mm mark with a 3.0N weight at the 10mm mark, apply the principle of moments. The total moments around the pivot must equal zero, meaning the moments from the weights on either side of the pivot balance each other out. The weight of the ruler can be considered concentrated at its midpoint, and the distances from the pivot to these weights must be factored into the moment calculations. The method involves summing the moments from both sides of the fulcrum and solving for the unknown weight of the ruler. This approach effectively uses the uniformity of the ruler and the known weight to find the solution.
Craptola
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Hello, run into a bit of a stumbling block studying moments perhaps someone could nudge me in the right direction.

Homework Statement


A uniform metre ruler is balanced horizontally on a knife edge at its 350mm mark, by placing a 3.0N weight on the rule at its 10mm mark. Calculate the weight of the ruler.


Homework Equations


Not entirely certain but I have to assume it involves
Moments = force x perpendicular distance and the principle of moments.


The Attempt at a Solution


This is where I'm stuck I've reasoned (probably wrongly) that:

(3N x 0.34m) + (y x b) = (z x a)

and y + z = the weight of the ruler.

Where y is the weight of the 350mm long side of the ruler

b is the distance between where the force y is acting (which I'm assuming is just its midpoint) and the pivot

z is the weight of the 650mm side of the ruler.

a is the distance between where the force z is acting (which again I'm assuming is its midpoint) and the pivot.

Not only am I extremely doubtfull that my above formula is correct I can't really see any way that I can determine the weight of the ruler form the information I've been given.
Any help would be greatly appreciated.
 
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Where does the 650mm come from? It was not stated in the problem.
 
The pivot is at the 350mm mark on the ruler which is 1m long, therefore there are 350mm of ruler before the pivot and 650mm after it.
 
If I assume correctly that the total length of the ruler is 650mm, you should sum moments at the fulcrum and set their sum to zero. On one side you have the weight at a certain distance from fulcrum. You also have the ruler weight that would contain the unknown total weight applied to each side of the fulcrum. Since ruler is uniform and you know what proportion is on each side of the fulcrum, you can sum those moments as well. Don't forget the weight of each overhanging side is assumed concentrated at the center of mass which you know because you know where the fulcrum is positioned. The equation you wind up with has one unknown, the weight. Solve for it.
 
Our posts overlapped. So the length is 1000mm. Same method applies. Sum moments at fulcrum and equate to zero. Only unknown is weight.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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