I don't understand my textbook.
Fh = Fa Cos θ
Where Fa is some pulling force applied, in-between horizontal and vertical.
Where Fh is force in the horizontal.
The Attempt at a Solution
Intuitively, if the angle of the force applied is at 45°, then the force in the horizontal and vertical is the same, and half of Fa.
Cos θ for 45° is 0.707. I was expecting 0.5.
What am I getting wrong? Thanks.