Calculating |vect.A + Vect.B + Vect.C|

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The discussion centers on calculating the magnitude of the sum of three mutually perpendicular unit vectors A, B, and C. It is clarified that while these vectors can align with the x, y, and z axes, they do not have to. The key point is that if vectors A and B are perpendicular, their dot product equals zero, and a third vector C can be defined as the cross product of A and B. The magnitude of the resultant vector is calculated using the Euclidean norm formula, which is the square root of the sum of the squares of the individual vectors. Understanding these principles is essential for solving the problem accurately.
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Homework Statement


vector A,B and C are mutually perpendicular unit vectors , then |vect.A + Vect.B + Vect.C| is equal to ...?


Homework Equations


unit vector=vector/magnitude


The Attempt at a Solution


since they are unit vectors and are perpendicular..they obviously are lying along x , y and z axes denoted by i , j , k (caps)
 
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Are we sure that this is a 3 dimensional incident?

Edit: I just realized, I clicked on "Advanced Physics" . . . going to go back to the Introductory forum now.

Good luck :).
 
Three unit vectors can be mutually perpendicular, but it is not necessary for the three vectors to coincide, or lie along, the coordinate axes.

Remember, if two arbitrary vectors A and B are defined such that A dot B = 0, then A and B are perpendicular. If we form the cross product such that C = A cross B, then the vectors A, B, and C will be mutually perpendicular.

The magnitude is given by the standard Euclidean norm Sqrt(A^2 + B^2 + C^2).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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