Calculating Vector Components with Given Magnitude: Solving for x and y

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SUMMARY

The discussion focuses on calculating the components of a vector with a magnitude of 4, where the x component is twice the y component. The magnitude formula used is |a| = √(x² + y²). By substituting x = 2y into the magnitude equation, the components can be determined. The resulting equations lead to the solution of x = 2.83 and y = 1.41, fulfilling the conditions set in the problem.

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Find a vector whose magnitude is 4 and whose x component is twice its y component.

I know that to calculate magnitude it is r= sqrt (x1 + x2)2 + (y1 + y2)2.

I also know that k(vector)= 4

I just am confused by the components (so x=2y ...)
 
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Let a=xi+yj

now |a|=4
so that 4=\sqrt{x^2+y^2}...(*)

You are told x=2y...can you use this fact and (*) to help you find x and y now?
 

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