Calculating Velocity in the Y-Direction: Seeking Help

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Homework Help Overview

The discussion revolves around calculating the velocity in the y-direction for a physics problem involving projectile motion or similar dynamics. Participants are seeking clarification on how to approach the calculation given the provided information.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express confusion regarding the calculation of velocity in the y-direction and question the absence of axis labels in the problem statement. There is a suggestion that the original poster may have meant to inquire about the velocity in the x-direction instead.

Discussion Status

The discussion is ongoing, with participants providing insights into the relationship between time, distance, and velocity. Some guidance has been offered regarding the constant nature of velocity in the x-direction, but no consensus has been reached on the y-direction calculation.

Contextual Notes

There are concerns about missing information, such as axis labels, which may affect the interpretation of the problem. The participants are working within the constraints of the problem as presented, which includes specific distances and the influence of gravity.

stringa
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I do not see how to calculate the velocity in the y-direction...any help is appreciated...all information is given

Problem is found here...

Thanks for the help


http://img214.imageshack.us/img214/5904/physicsxn6.png
 
Last edited by a moderator:
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I do not see how to calculate the velocity in the y-direction...any help is appreciated...all information is given

Problem is found here...

Thanks for the help


http://img214.imageshack.us/img214/5904/physicsxn6.png
 
Last edited by a moderator:
I do not see any axis lables. What is y? what is x?
 
You probably meant the velocity in the x-direction.

You calculated the time it takes a water drop exiting the soaker to drop through a height of 1 meter. This is also the time it takes the same water drop to travel a horizontal distance of 10 meters (during the same time). So its horizontal speed is

[tex]v_x = \frac{horizontal\ distance\ travelled}{time\ to\ travel\ this\ distance}[/tex]
 
y is the direction of gravity.

Just use the distance and the fact that the velocity in the x-direction remains constant to calculate the velocity given you know the time.
 
Last edited:

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