Calculating Voltage Across a Capacitor

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The discussion focuses on calculating the voltage across a capacitor in a circuit with a time constant of τ=7s. The initial current is correctly calculated as 0.2A, leading to a computed current at 5 seconds of 0.0979A. Using Ohm's law, the voltage is calculated as 145.73V; however, the expected correct answer is 153V. The confusion arises around whether V=IR applies to the voltage across a capacitor. Clarification is sought on the correct approach to determine the voltage across the capacitor.
roam
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Homework Statement



[PLAIN]http://img189.imageshack.us/img189/4555/capacitorh.jpg


Homework Equations



I(t)=I_0 e^{-t/\tau} (current as a function of time for a capacitor being charged)


The Attempt at a Solution



The time constant of the circuit is τ=RC=7s. And the initial current in the circuit is

v/Req=300/1489=0.2A (I know this is correct)

Now pluging into the equation:

I(5)=0.2 e^{-5/7}=0.0979 \ A

V=IR= 0.0979 \ A \times 1489 \Omega = 145.73 \ V

But the correct solution must be 153V. I'm very confused, what's wrong with my working? :confused:
 
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Is V=IR the voltage across a capacitor? ehild
 
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