Calculating Voltage at Terminal A in a Two-Terminal Circuit

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Homework Help Overview

The discussion revolves around calculating the voltage at terminal A with respect to terminal B in a two-terminal circuit involving resistors. The problem includes considerations of series and parallel resistor configurations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between voltage and resistance in the context of series and parallel circuits. Questions arise regarding the relevance of a 1 Ohm resistor and its impact on the overall circuit analysis. There is also a discussion about verifying voltage calculations using different methods.

Discussion Status

Some participants have provided guidance on interpreting the circuit, suggesting that the 1 Ohm resistor can be ignored under certain conditions. There is acknowledgment of correct calculations for the voltage across a 3 Ohm resistor, with alternative verification methods being discussed.

Contextual Notes

Participants mention potential confusion regarding the role of specific resistors in the circuit and the assumptions made about current flow. There is also a correction regarding a unit error in voltage versus current.

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Homework Statement



help please! i am trying to find V at terminal A with respect to B

Homework Equations


V=IR
I=V/R

The Attempt at a Solution


so this is my thought process:
the answer should be 10 V because the voltage is the same for a parallel resistor, but the thing that throws me off is that terminal is has a resistance of 1 Ohm so I'm not sure if my answer is right. help please and thank you.
 
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That's incorrect. The 1 Ohm resistor is just a wire as there is no current flowing through it so it can be ignored. So now you basically just have that first loop. The voltage across terminals A and B is the same as the voltage across the 3 Ohm resistor, right? How can you find the voltage across that resistor?
 
okay. with that info, i got the voltage across the 3Ohm resistor to be 6.00 A

is this right?

because i added 2 and 3 since it is in series so that gives total resistance
v=IR
I=V/R
I=10/5
I=2
V=IR for the 3Ohm resistor
V=2(3) = 6
 
Yep that's right. Also, if you want to verify your answer you could do a Voltage divider equation... V = 10V * (3 / (3+2) ) = 6 or KCL analysis at that top node so (V1 - 10V)/2 + (V1 - 0)/3 = 0 and then solve for V1 which ends up being 6V.

Of course the way you did it is the easier way, I'm just showing you other approaches and verifying your answer :p
 
thanks for the help. and i meant 6.00 V, not 6.00 A but I'm sure you figured that out
 

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