Calculating Voltage Drop Across 5kOhm Resistor

[myoplex11]

Homework Statement

A 6V DC voltage source is connected across both a 5kohm resistor and a 10 nF capacitor in series. The voltage drop across the resistor is what?
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Homework Equations

Q=CV

The Attempt at a Solution

Q= (10*10^-9 F)(5000ohms)

 

[asd1249jf]

Homework Statement

A 6V DC voltage source is connected across both a 5kohm resistor and a 10 nF capacitor in series. The voltage drop across the resistor is what?
Reply With Quote

Homework Equations

Q=CV

The Attempt at a Solution

Q= (10*10^-9 F)(5000ohms)

Q = CV does not have anything to do with finding the voltage drop across the resistor. Q here refers to the charge, C is the capacitance and V is the voltage.

Did you learn about Kirchoff's law? Use Kirchoff's voltage law to solve this.

 

[myoplex11]

no we did not learn kirckoffs law

 

[pooface]

Did you learn how a capacitor works? KVL is really not needed.

Think what happens when the capacitor is not charged at all and what happens when it is fully charged.

There is not enough information given here in my opinion.