Minimizing the voltage drop across a capacitor (solution shown)

[Sunwoo Bae]

Homework Statement

Shown in the text

Relevant Equations

Q = CV

capacitors in series
capacitors in parallel

The following is the question and the solution to the question.

I understand the solution to the part where you find the Ceq and derive Qeq from the equation Q = Ceq*V.
However, I do not understand where V1 = V0-V2 come from.
When calculating the minimum voltage, how do you come up with the equation V1 = V0-V2, and why is V3 not taken to account?

 

[Istiak]

I do not understand where V1 = V0-V2 come from.

given and total potential difference is always same.
Here given potential difference is $V_0$ and total potential difference is $V_1+V_2$

So $V_0=V_1+V_2$

 

[Orodruin]

Homework Statement:: Shown in the text
Relevant Equations:: Q = CV

capacitors in series
capacitors in parallel

The following is the question and the solution to the question.
View attachment 296217

I understand the solution to the part where you find the Ceq and derive Qeq from the equation Q = Ceq*V.
However, I do not understand where V1 = V0-V2 come from.
When calculating the minimum voltage, how do you come up with the equation V1 = V0-V2, and why is V3 not taken to account?

Are you familiar with Kirchhoff’s laws?