Calculating Voltage Drop and Current Through a Voltmeter

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Homework Help Overview

The discussion revolves around calculating the voltage drop across a voltmeter and the current through it, given specific resistances and a current through a resistor. The problem involves concepts from electrical circuits, particularly dealing with parallel resistances and Ohm's Law.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore how to apply the given current and resistances to find the voltage drop across the voltmeter and the current through it. Questions arise about whether to find the source voltage or the combined resistance of the circuit elements.

Discussion Status

Some participants have provided hints and guidance regarding the relationships between voltage drops in parallel circuits. There is acknowledgment of correct reasoning in parts of the problem, but also indications of potential errors that need to be clarified. The discussion is ongoing with participants checking each other's understanding.

Contextual Notes

Participants note the importance of correctly interpreting the power of ten in calculations and emphasize the need for clear equations for better understanding. There is a focus on the potential difference across parallel components without needing the total voltage of the source.

badd99
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Homework Statement


Voltmeter has a internal resistance of 10M ohms and the resistor has a resistance of 100,000ohm. The current through the resistor is 1mA.
a)What is the voltage drop across the voltmeter?
b)What is the current through the voltmeter?


Homework Equations


V=IR is all you should need


The Attempt at a Solution


I am missing something really small (have taken the class already) but I'm stuck. I am stuck with how to apply the 1mA current. Do I need to use that to find the voltage of the source? Or do I find the overall resistance of the reistor and parallel voltmeter then use the 1mA somehow?

Please help me! Thank you!
 
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You don't need to find the voltage of the source, or the combined resistance of the parallel resistor and voltmeter. Its simpler than that. You are given the resistance and current through the resistor, so what can you say about the voltage drop over the resistor? And what does this tell you about the voltage drop over the voltmeter?
 
Well given 1ma over the resistor you can do V = (1E-3)(100,000) which is the voltage drop over the resistor...without the total voltage how can I find the voltage drop over the volt meter? current through voltmeter?
 
Hint: Potential Difference across all parallel resistors is same.
 
so if its V=(1E-3)(100,000) = 100 v across the resistor its 100 V across the voltmeter for part a?

For b you then take 100v=I(10E7) = 1E-6 A?
 
Yes. Note that the voltage refers to potential difference and not always to source voltage
 
badd99 said:
so if its V=(1E-3)(100,000) = 100 v across the resistor its 100 V across the voltmeter for part a?

For b you then take 100v=I(10E7) = 1E-6 A?

You got part (a) right. And I think you've got the right idea for part (b), but I think you went wrong in part (b). Check you have the right power which 10 is raised to. And write out the equations properly! It makes them easier for you and us to read when you write them out properly. (And your teacher will be able to read them easier, more importantly).
 
I see my error, thank you guys very, very much for the help! Can't thank you enough!
 
no worries :)
 

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