Current through a voltmeter with internal resistance

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SUMMARY

The discussion centers on calculating the current through a voltmeter with an internal resistance of 3 ohms, connected in series with a 2 ohm and a 5 ohm resistor, powered by a 10 V supply. The equivalent resistance of the 5 ohm resistor and the voltmeter's internal resistance is determined to be 1.815 ohms, resulting in a measured voltage of 4.83 V across the voltmeter. The current through the entire circuit is calculated as 1.64 A, confirming that the current through the voltmeter is not the same as the total circuit current.

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Homework Statement


You have a power supply of 10 V. It is connected in series to a 2 ohm resistor and a 5 ohm resistor.

You take the voltage across the 5 ohm resistor with a voltmeter that has an internal resistance of 3 ohms. What is the current through the voltmeter?

Homework Equations


The Attempt at a Solution


So I figured out the equivalent resistance of 5 ohms and 3 ohms is 1.815 ohms. Then the voltage across that is 4.83 V, which is the voltage read by the voltmeter.

Is the current going through the voltmeter just the same as the current going through the entire circuit? (So 10/(2 + 1.815))

Or is it the current just through the voltmeter's 3 ohm internal resistance? (Which I found to be 1.64 A)?
 
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Equivalent resistance R = 5*3/8 = ? Check this calculation.
 

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