- #1
RJLiberator
Gold Member
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Question: What volume of a 0.835 M solution of Na2SO4 do you have if there are 0.0534 mol of Na+ present in the solution?
What I did: Since we have 0.0534 moles of Na+ ions in the Na2SO4 molecule, I used that for the equation. Since 0.0534 moles is in a 1:1 ratio with Na2SO4 I can conclude we have 0.0534 moles of Na2SO4.
M = Moles/Volume
0.835M = 0.0534moles of Na2SO4/V
Solving, I get 6.40x10^-2L
Is my reasoning correct?
What I did: Since we have 0.0534 moles of Na+ ions in the Na2SO4 molecule, I used that for the equation. Since 0.0534 moles is in a 1:1 ratio with Na2SO4 I can conclude we have 0.0534 moles of Na2SO4.
M = Moles/Volume
0.835M = 0.0534moles of Na2SO4/V
Solving, I get 6.40x10^-2L
Is my reasoning correct?