Calculating Wavelength in Young's Interference Experiment

[elementozzy]

So I got a warning for just posting questions so I'll do as best as I can to try and put effort lol

Homework Statement

A Young's interference experiment is performed with monochromatic light. The separation between the slits, d, is .50 mm, and the interference
pattern on a screen L = 3.3 m away shows the first maximum y1 = 3.4 mm from the center of the pattern. What is the wavelength?


GIVEN DATA

d=.50mm

L=3.3m

y1= 3.4mm

Homework Equations

Yn=(nλL)/d

The Attempt at a Solution

I need to know if I'm attempting this right.

I started off by plugging in y1=3.4mm, L=3.3m and d=.50mm

Pretty simple.
3.4=(nλ3.3)/.5

1.7=(nλ3.3)

.5151...=λ

?

Am I right by plugging in 1 for n?

 

[dauto]

Quoting from the text you provided "first maximum y1 = 3.4 mm".

 

[elementozzy]

So... Am I right?

 

[dauto]

So... Am I right?

Do you need to ask? the formula given is for y_n, you were given y₁, what do you think n is?

 

[elementozzy]

Oh I just needed to make sure. So yn(subscript), whatever is in the subscript is just n?