Calculating Weight with Proportions for Balls of Different Sizes

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SUMMARY

The discussion focuses on calculating the weight of a ball with a diameter of 9.0 inches, given that a ball with a diameter of 4.50 inches weighs 18.0 ounces. The correct approach involves understanding that volume is proportional to the cube of the radius, not just the radius itself. The formula for the volume of a sphere, V = 4/3πr³, is essential for solving the problem. The final calculation shows that the weight of the larger ball is 144 ounces, confirming the relationship between volume and weight based on density.

PREREQUISITES
  • Understanding of volume calculations for spheres
  • Knowledge of proportions and ratios
  • Familiarity with the formula for the volume of a sphere, V = 4/3πr³
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the relationship between volume and density in physical objects
  • Learn about dimensional analysis in physics
  • Explore more complex problems involving proportions and geometric shapes
  • Review the derivation and applications of the volume formula for spheres
USEFUL FOR

Students in mathematics or physics, educators teaching geometry and proportions, and anyone interested in applying mathematical concepts to real-world problems involving density and volume.

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Proportion Help. (from Ratio, Proportion, and Variations)

Homework Statement


A ball 4.50 in in diameter weighs 18.0 oz. What is the weight of another ball of the same density that is 9.0 in in diameter?


Homework Equations


Is this set up as a proportion? Or something else? I read the similar figures things but that does not seem to work.


The Attempt at a Solution



I set it up like a proportion: 4.50/9 = 18/x this comes up with 36 oz. But this is not the right answer. The answer is supposed to be 144 oz. But they don't show how they got it. The book doesn't have anything like this in its examples so I am stuck.

Is this not set up like a proportion? Or is there another type of formula I should be using?
 
Last edited:
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What's the relation between the volume of a sphere and its radius?
 
Yes, it is a proportion- but not just "volume is proportional to radius"- volume is proportional to a power of the radius: which power? As Dick said, "What is the relation between the volume of a sphere and its radius?"
 
ok, so V= 4/3piD/2^3

then 18 = 4/3pi (4.5/2)^3
------------------
2 = 4/3pi (4.5)^3 right?

cancellation gives me 18 / x = 1/8 / 1 which is 144 ! Great! thanks guys!
 

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