Calculating Weight with Proportions for Balls of Different Sizes

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Homework Help Overview

The problem involves calculating the weight of a ball based on its diameter and density, specifically comparing a 4.50-inch diameter ball weighing 18.0 oz to a 9.0-inch diameter ball. The original poster questions whether the setup is appropriate for a proportion or if another method should be used.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to set up a proportion but questions its validity after arriving at an incorrect answer. Participants discuss the relationship between volume and radius, suggesting that volume is proportional to the cube of the radius.

Discussion Status

Some participants provide insights into the mathematical relationships involved, particularly focusing on the volume of spheres and how it relates to diameter. There is a recognition of the need to consider the correct power of the radius in the calculations.

Contextual Notes

The original poster notes that the textbook does not provide examples relevant to this problem, indicating a potential gap in resources or guidance for similar calculations.

06Sport
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Proportion Help. (from Ratio, Proportion, and Variations)

Homework Statement


A ball 4.50 in in diameter weighs 18.0 oz. What is the weight of another ball of the same density that is 9.0 in in diameter?


Homework Equations


Is this set up as a proportion? Or something else? I read the similar figures things but that does not seem to work.


The Attempt at a Solution



I set it up like a proportion: 4.50/9 = 18/x this comes up with 36 oz. But this is not the right answer. The answer is supposed to be 144 oz. But they don't show how they got it. The book doesn't have anything like this in its examples so I am stuck.

Is this not set up like a proportion? Or is there another type of formula I should be using?
 
Last edited:
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What's the relation between the volume of a sphere and its radius?
 
Yes, it is a proportion- but not just "volume is proportional to radius"- volume is proportional to a power of the radius: which power? As Dick said, "What is the relation between the volume of a sphere and its radius?"
 
ok, so V= 4/3piD/2^3

then 18 = 4/3pi (4.5/2)^3
------------------
2 = 4/3pi (4.5)^3 right?

cancellation gives me 18 / x = 1/8 / 1 which is 144 ! Great! thanks guys!
 

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