Calculating Wheatstone Bridge with R1=600, R2=R3=R4=400, V Supply=10V

Click For Summary
SUMMARY

The discussion focuses on calculating the output voltage (Vout) in a Wheatstone bridge configuration with specific resistor values: R1=600 ohms, R2=R3=R4=400 ohms, and a supply voltage of 10V. The initial formula used for calculation was incorrect, leading to confusion about the balance of the bridge. The correct approach involves recognizing that one side of the bridge must have equal resistors, resulting in a voltage of 5V, while the other side with R1 and R2 results in a voltage of 4V, yielding a 1V difference between the junctions. Additionally, the discussion touches on using strain gauges and the importance of proper resistor values for accurate measurements.

PREREQUISITES
  • Understanding of Wheatstone bridge configurations
  • Familiarity with voltage calculations in electrical circuits
  • Knowledge of strain gauge principles and applications
  • Basic concepts of resistance and Ohm's Law
NEXT STEPS
  • Study Wheatstone bridge voltage calculations in detail
  • Learn about the application of strain gauges in load measurements
  • Research the effects of resistor values on bridge balance
  • Explore the use of galvanometers in Wheatstone bridge setups
USEFUL FOR

Electrical engineers, physics students, and professionals working with strain gauges and Wheatstone bridges will benefit from this discussion, particularly those involved in precise voltage measurements and load testing applications.

orla22
Messages
22
Reaction score
0
if r1 has value of 600 and r2=r3=r4=400 ohms. supply voltage is 10v.
im getting the wrong answer and do not know how.

im using [(R4R2 - R3R1) / (R1+R4)(R2+R3)] * VS

i get an answer of [160000 - 240000 / (1000)(800)] * 10 = [-80000 / 80000] * 10 = -1ohm

but this is the incorrect answer. where am i going wrong?
 
Physics news on Phys.org
Your Wheatstone bridge is not balanced. You cannot have r1=600 and r2=r3=r4=400 ohms. Check all your resistances.
 
Since you supplied us with all four resistance values I'm assuming that you're looking for the voltage across the bridge. If that is the case then your formula is incorrect. Check Wikipedia.
 
I think you have the right answer but the wrong units. Assuming you are looking for the voltage between the junctions at the centre of the bridge.

One side of the bridge must have two equal resistors (both 400 ohms) so the voltage must be half the supply voltage. 5 v

The other side must have a 600 and a 400 ohm resistor. So, it must have 4/10 of the supply voltage at the junction. 4 v

So there must be 1 volt difference between the two junctions. Polarity depends on how you measure it.
 
Wheatstone bridges are designed to use a sensitive galvanometer across the two junctions at the center of the bridge, and to zero the current thru the galvanometer using the bridge. If you are using a 120 ohm strain gauge, then you want (for example) three 400 ohm resistors, and a 280 ohm setting on the bridge in series with the strain gauge. Even better if you can use three 120 ohm resistors, because then you can get a direct reading of the strain gauge resistor on the bridge setting..
 
hi all, could you possibly help me with this problem?

R1 and R2 are 2 guages with resistance of 100 ohm.
A steel bar has diameter 45mm and modulus of steel bar is 170GN/m^2 and gauge factor of 2. How would I calculate Vout when a load of 35kN is applied?

i know what the Vout formula is and stress = tensile strain x YM.

thanks
 

Attachments

  • WS.jpg
    WS.jpg
    11.8 KB · Views: 555

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 31 ·
2
Replies
31
Views
8K
  • · Replies 4 ·
Replies
4
Views
14K