Why Is My Resistive Bridge Calculation Resulting in Different Voltages?

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Altairs
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Homework Statement


I was trying to apply the formula of bridge


Homework Equations


[tex]V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})[/tex]


The Attempt at a Solution


File is attached...Small numbers with resistor names are their values in ohms...
the answer I get is 6v...Here it is 1.5 v...
 

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Altairs said:

Homework Statement


I was trying to apply the formula of bridge

Homework Equations


[tex]V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})[/tex]

The Attempt at a Solution


File is attached...Small numbers with resistor names are their values in ohms...
the answer I get is 6v...Here it is 1.5 v...

The equation should be:
[tex]V_{o} = [(\frac{1}{1+R4/R3})-(\frac{1}{1+R2/R1})]V_s[/tex]
With[tex]V_s = 3V[/tex] you could never have [tex]V_o = 6V[/tex] with a totally passive circuit.