Why Is My Resistive Bridge Calculation Resulting in Different Voltages?

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SUMMARY

The discussion centers on the calculation of output voltage (V_o) in a resistive bridge circuit using the formula V_{o} = [(\frac{1}{1+R4/R3})-(\frac{1}{1+R2/R1})]V_s. The original calculation yielded 6V, which is incorrect given a supply voltage (V_s) of 3V. The correct output voltage should not exceed the supply voltage in a passive circuit, confirming that the calculated output of 1.5V is accurate.

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Homework Statement


I was trying to apply the formula of bridge


Homework Equations


V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})


The Attempt at a Solution


File is attached...Small numbers with resistor names are their values in ohms...
the answer I get is 6v...Here it is 1.5 v...
 

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Altairs said:

Homework Statement


I was trying to apply the formula of bridge

Homework Equations


V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})

The Attempt at a Solution


File is attached...Small numbers with resistor names are their values in ohms...
the answer I get is 6v...Here it is 1.5 v...

The equation should be:
V_{o} = [(\frac{1}{1+R4/R3})-(\frac{1}{1+R2/R1})]V_s
WithV_s = 3V you could never have V_o = 6V with a totally passive circuit.
 

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