Calculating Work and Kinetic Energy for Moving Blocks with a Compressed Spring

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SUMMARY

The discussion focuses on calculating the work and kinetic energy for two blocks, A and B, connected by a spring. Block A, weighing 161 lb, moves downward at 5 ft/s while the spring is compressed by 6 inches. The coefficient of friction between block B and the plane is 0.2, and the weight of block B is 193 lb. The solutions provided indicate that block A falls 4.78 ft before coming to a stop and will subsequently move back upward.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of work-energy principles (W=ΔT)
  • Familiarity with spring mechanics (energy stored in a spring = ½kx²)
  • Basic concepts of friction and its effects on motion
NEXT STEPS
  • Study the application of Newton's second law in multi-body systems
  • Learn about the work-energy theorem in the context of mechanical systems
  • Investigate how to calculate spring constants from compression data
  • Explore second-order differential equations in mechanical dynamics
USEFUL FOR

Students in physics or engineering courses, particularly those studying dynamics and energy systems, will benefit from this discussion.

xzibition8612
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Homework Statement



Block A is moving downward at 5 ft/s at a certain time when the spring is compressed 6 inches. The coefficient of friction between block B and the plane is 0.2, the pulley is light, and the weights of A and B are 161 and 193 lb, respectively.

a) Find the distance that A falls from its initial position before coming to zero speed
b) Determine whether or not body A will start to move back upward

Homework Equations



F=ma
W=ΔT
work by spring = (-1/2)(x)

The Attempt at a Solution


The answers are a) 4.78 ft b) A will start back upward

No idea how to start. I suppose I apply F=ma to each A and B separately? Then somehow invoke the work energy equation to figure it out? How do I handle the spring? And the spring compressed 6 inches confuses me. Thanks for the help.
 

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xzibition8612 said:
W=ΔT
work by spring = (-1/2)(x)
The energy stored in a spring = ½kx²

As mass A loses potential energy, that energy reappears in the system in other forms. Write the equation that accounts for this. I presume that, since the spring has compressed 6", then the masses have moved the same 6". This should allow you to find the spring constant, k.

(Your sketch shows the spring stretching, whereas I expect it should be drawn as a compression spring.)

Beyond this, I'm afraid I can't help further. I think you'd be looking at a 2nd order DE?
 

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