Calculating Work Done by a Pitcher: Physics Homework [SOLVED]

  • Thread starter Thread starter Heat
  • Start date Start date
  • Tags Tags
    Work Work done
Click For Summary
SUMMARY

The discussion focuses on calculating the work done by a pitcher when throwing a baseball, specifically using the formula for kinetic energy. The baseball's mass is 0.145 kg, and it leaves the pitcher's hand at a speed of 32.5 m/s. The correct calculation for work done is derived from the kinetic energy formula K = 1/2 mv², leading to a total work done of 76.58 Joules. The importance of correctly applying the kinetic energy formula is emphasized to arrive at the accurate result.

PREREQUISITES
  • Understanding of kinetic energy formula (K = 1/2 mv²)
  • Basic knowledge of physics concepts related to work and energy
  • Familiarity with units of measurement (Joules, kilograms, meters per second)
  • Ability to perform algebraic calculations
NEXT STEPS
  • Study the principles of work and energy in physics
  • Learn about the conservation of energy in mechanical systems
  • Explore real-world applications of kinetic energy calculations
  • Investigate the effects of air resistance on projectile motion
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of work and energy in sports contexts.

Heat
Messages
272
Reaction score
0
[SOLVED] Work Done by Pitcher

Homework Statement



A baseball leaves a pitcher's hand at a speed of 32.5 m/s. The mass of the baseball is 0.145 kg. You can ignore air resistance.

How much work has the pitcher done on the ball by throwing it?

The Attempt at a Solution



velocity initial = 32.5
velocity final = 0 (it has to stop eventually right?)
mass of ball = .145

K = mv^2

K1 = (.145)(32.5)^2 = 153.16
K2 = (.145)(0)^2 = 0

Wtotal = K2-K1

Wtotal = 0 - 153.16

:confused:

Solution: 76.6 J
 
Physics news on Phys.org
Heat said:
How much work has the pitcher done on the ball by throwing it?
They are talking about the work done by the pitcher in taking a ball from rest to its top speed as it leaves his hand.

K = mv^2
That's not quite right.
 
haha,

I forgot it was

K = 1/2mv^2

ok, now that I got 76.58.

ah, I see now.

so it's this then

K2 = .5(.145)(32.5)^2 = 153.16
K1 = .5(.145)(0)^2 = 0

Wtot = K2-K1 = 76.58
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
3
Views
2K