Calculating Work on an Inclined Plane

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SUMMARY

The discussion focuses on calculating the effort force required to pull a cart weighing 7.6734 N up a frictionless inclined plane. The relevant equations include work (W=FΔXcosθ) and efficiency calculations. Participants express confusion regarding the efficiency of a frictionless ramp compared to a ramp with friction, questioning whether the input force of 7.6734 N is appropriate for their calculations. The key takeaway is that when calculating work done on an inclined plane, only the force component parallel to the incline should be considered.

PREREQUISITES
  • Understanding of basic physics concepts such as force, work, and efficiency
  • Familiarity with inclined plane mechanics
  • Knowledge of trigonometric functions related to angles
  • Ability to perform calculations involving vectors and components
NEXT STEPS
  • Study the concept of force components on inclined planes
  • Learn about the implications of friction on efficiency in mechanical systems
  • Explore the principles of work-energy theorem in physics
  • Investigate real-world applications of frictionless systems in engineering
USEFUL FOR

Students in physics, educators teaching mechanics, and engineers interested in the efficiency of mechanical systems.

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Homework Statement


How do you find the effort force of pulling a cart up a ramp with no friction and you know that the weight of the cart is 7.6734 N?


Homework Equations


W=F[tex]\Delta[/tex]Xcos[tex]\theta[/tex]
Efficiency=(work output / work input) x 100

The Attempt at a Solution


My main goal is to compare the efficiency of an ideal frictionless machine (the ramp) to the efficiency of a ramp with friction that I already have the calculations for.
However my efficiency for the frictionless ramp is less than the efficiency for on with friction. Could this be right?
When I'm solving the work equation in order to get the work input and output I use 7.6734 for the force. Is this right?
 
Physics news on Phys.org
When you calculate work done from a constant force, you need only think about the force component parallel to the line of motion. What is the forcecomponent parallel the to inclined plane?
 

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