Calculating Work Using Green's Theorem

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SUMMARY

This discussion focuses on applying Green's Theorem to calculate the work done by the vector field ∇θ on a particle moving around a closed curve C, defined by the piecewise smooth curves C1 and C2. The vector field is given by θ(x,y,z) = x²z² + 3yz + 2x, leading to the gradient ∇θ = (2xz² + 2, 3z, 2zx² + 3y). The correct approach involves breaking the path integral into two sections, integrating directly over C1 and C2, and performing the dot product with ∇θ. The discussion emphasizes the importance of correctly interpreting the integral and the application of Green's Theorem.

PREREQUISITES
  • Understanding of Green's Theorem in vector calculus
  • Familiarity with vector fields and gradients
  • Knowledge of parametric equations for curves
  • Ability to perform line integrals and dot products
NEXT STEPS
  • Study the application of Green's Theorem in various contexts
  • Learn about line integrals and their computation in vector fields
  • Explore the properties of gradients in multivariable calculus
  • Practice solving problems involving piecewise smooth curves
USEFUL FOR

Students preparing for mathematics exams, particularly those studying vector calculus, and anyone looking to deepen their understanding of Green's Theorem and its applications in physics and engineering.

farso
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Hi everyone.

I am going through examples for maths exams and am unsure on the final part of a question I am attempting so hoping you may help me?

Homework Statement



"Let C be the closed, piecewise smooth curve comprising individual curves C1 and C2
defined by r1 = (x, x2, 1) and r2 = (x,+√x, 1), respectively, with 0 ≤ x ≤ 1, see
Figure 1. Evaluate the work done by the vector field ∇ on a particle moving around
curve C once in the anticockwise direction, i.e. directly compute the integral

[tex]\oint \nabla \theta (x,y,z) dr[/tex]"


Homework Equations



As per above/below

The Attempt at a Solution



[tex]\theta (x,y,z) = x^2z^2+3yz+2x[/tex]

hence

[tex]\nabla \theta (x,y,z) = (2xz^2+2, 3z, 2zx^2+3y)[/tex]


So, using green's theorem (I think this is correct)

[tex]\oint \nabla \theta (x,y,z) dr[/tex]

is the same as

[tex]\int_{y=x^2}^{y=\sqrt{x}}\int_0^1 \nabla \theta (x,y,z) dxdy[/tex]

I think this is correct, but can't seem to find the next "step". Id be grateful if anyone could tell me if I am on the right track, and maybe show me where to go on the next step?

Thanks in advance
 
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farso said:
"Let C be the closed, piecewise smooth curve comprising individual curves C1 and C2
defined by r1 = (x, x2, 1) and r2 = (x,+√x, 1), respectively, with 0 ≤ x ≤ 1, see
Figure 1. Evaluate the work done by the vector field ∇ on a particle moving around
curve C once in the anticockwise direction, i.e. directly compute the integral

[tex]\oint \nabla \theta (x,y,z) dr[/tex]"

Maybe I'm misinterpreting the question, as I can't see Figure 1, but to me, the work done by the vector field [itex]\mathbf{\nabla}\theta[/itex] would involve a dot product, and would be a scalar quantity:

[tex]W=\oint \mathbf{\nabla}\theta\cdot d\textbf{r}[/tex]



So, using green's theorem (I think this is correct)

[tex]\oint \nabla \theta (x,y,z) dr[/tex]

is the same as

[tex]\int_{y=x^2}^{y=\sqrt{x}}\int_0^1 \nabla \theta (x,y,z) dxdy[/tex]

This makes no sense...Where exactly did you use Green's theorem and how?

Instead, just break the path integral into two sections (over [itex]C_1[/itex] and [itex]C_2[/itex]) and integrate it directly... what is [itex]d\textbf{r}[/itex] for the first section? How about the second?
 
Hi

Thanks for the speedy reply!

Looking at it again and the definition of greens theorem I am not entirely sure why I chose to try and use it.

Are you suggesting that I do it as:

[tex]\oint \nabla \theta (x,y,z) dr =[/tex][tex]\int_{0}^{1} \nabla \theta (x,y,z) dr_1[/tex] + [tex]\int_{0}^{1} \nabla \theta (x,y,z) dr_2[/tex]

where [tex]dr_1 = (1,x^{2},0)[/tex] and [tex]dr_2 = (1, -(1/2)x^{-1/2}, 0)[/tex]

So... If this is correct, do I just do the dot product of that with [tex]\nabla \theta (x,y,z)[/tex]?
 
Last edited:

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