Calculating x and y Components of a Force on a Block from Rope Pulling

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The discussion focuses on calculating the x and y components of a force exerted on a block by a rope pulling at a tension of 225 N at a 30-degree angle to the horizontal. The x-component is determined using the formula F_x = F * cos(θ), resulting in F_x = 225 N * cos(30°), while the y-component is calculated using F_y = F * sin(θ), yielding F_y = 225 N * sin(30°). Participants emphasize the importance of understanding trigonometric relationships and suggest drawing a diagram to visualize the components effectively.

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1. A rope is attached to a block. The rope pulls on the block with a force of 225 N, at an angle of 30 degrees to the horizontal (this force is equal to the tension in the rope).

What is the x-component of the force on the block due to the rope?
What is the y-component of the force on the block due to the rope?




3. I have tried dividing the force by the cos of 30. Thats all I can think of to do as I missed class the day we went over this but any help would be greatly appreciated!
 
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cjtaylor said:
1. A rope is attached to a block. The rope pulls on the block with a force of 225 N, at an angle of 30 degrees to the horizontal (this force is equal to the tension in the rope).

What is the x-component of the force on the block due to the rope?
What is the y-component of the force on the block due to the rope?




3. I have tried dividing the force by the cos of 30. Thats all I can think of to do as I missed class the day we went over this but any help would be greatly appreciated!

Think about the relationships between sine, cosine, opposite side, adjacent side, and hypotenuse. Thinking about the Pythagorean theorem couldn't hurt either.
 
First off draw a diagram of the question. Then label the horizontal and vertical axis with the two components then
collinsmark said:
Think about the relationships between sine, cosine, opposite side, adjacent side, and hypotenuse.
 

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