# Calculation on a water cooled compressor

How can i calculate the water temperatur in step 3? Do i need more information?
We can assume the water temperatur in step 2 is anything between 288 and 313K.
If anyone knows how to calculate step 4, ill take that as well.

Related General Engineering News on Phys.org
Some items needed:
1) flow rate of glycol & sea water
2) material being compressed
3) inlet & outlet temperatures of material being compressed

Usually you can obtain the heat transfer requirements from the compressor supplier.

Depending on the type of exchanger, step 2 could be 288 K. That information is also needed.

mariuog
Some items needed:
1) flow rate of glycol & sea water
2) material being compressed
3) inlet & outlet temperatures of material being compressed

Usually you can obtain the heat transfer requirements from the compressor supplier.

Depending on the type of exchanger, step 2 could be 288 K. That information is also needed.
The flow rate of water+glycol is 6,8 liter/s
The material been compressed is air, i dont know the inlet & outlet temperatures, but i know the max temperature of the air inlet is 313K but reference conditions is 293K.
Can you make an assumption of the rest of the values and show how to calculate the temperatures in step 3? Lets say step 2 is 300K(you can choose something else if you want to)
Thank you so much for the answer!

I looked in my old work files, it seems a 300 kW compressor needs about 20 kW cooling. This is from manufacturer's data, not computable from standard conditions. So the 6.8 l/s flow of glycol solution will be heated by 20 kW. When I was working, I did all my calculations in English units (actually American units, now since we are the only one using them nowadays), so you will have to calculate the temperature rise in K using the specific heat of the glycol solution, since I don't have this data in SI units.

V. Eddy

Chestermiller
Mentor
OP: Do you know the air flow rate? Have you given us all the information?