Use spherical coordinates to evaluate the triple integral z dV where Q is the solid that lies between x^2+y^2+z^2=1 and x^2+y^2+z^2=4.
Not sure what goes here :P
The Attempt at a Solution
I've gotten everything set up, im having problems with boundaries I think. Currently I am using 0 to 2[tex]\pi[/tex] for [tex]\vartheta[/tex], 0 to [tex]\pi[/tex] for [tex]\varphi[/tex] and 1 to 2 for [tex]\rho[/tex]. When solving, I get zero as my final answer, and since I'm not clear on the conceptual meaning of a triple integral that isn't of a function that equals 1 (volume) I don't know if this answer makes sense.