Calculus based physics - Energy

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SUMMARY

The discussion focuses on two physics problems involving energy conservation and potential energy calculations. The first problem involves a conservative force defined by Fx=(22-2.0x)N, where the potential energy at x=0 is +40 J, leading to a potential energy of -24 J at x=4 m after integration. The second problem examines a 1.5 kg block dropped onto a spring with a spring constant of k=300 N/m, requiring the application of energy conservation principles to determine the kinetic energy after the block compresses the spring by 0.10 m.

PREREQUISITES
  • Understanding of conservative forces and potential energy
  • Knowledge of energy conservation principles in mechanics
  • Ability to perform integration in physics contexts
  • Familiarity with spring mechanics and Hooke's Law
NEXT STEPS
  • Study the concept of conservative forces in physics
  • Learn about energy conservation in mechanical systems
  • Practice integration techniques for potential energy calculations
  • Explore Hooke's Law and its applications in spring mechanics
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Students studying calculus-based physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to enhance their understanding of these concepts.

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Homework Statement


As a particle moves along the x-axis it is acted upon by a single conservative force given by Fx=(22-2.0x)N where x is in m. The potential energy associated with this force has the value +40 J at the origin (x=0). What is the value of the potential energy at x=4 m?


Homework Equations





The Attempt at a Solution



Well, you have to move it so that it is Fx= 2xdx - 20dx ( -dU/dx ) so you have this equation. Then I integrated it and got x^2-20x+C... C is 40 in this case, so you have x^2-20x+40. Since it says potential energy at x=4, I plugged in the 4 and got 4^2-20*4+40= -24. That's not correct, though.


Homework Statement


A spring (k=300N/m) is placed in a vertical position with its lower end supported by a horizontal surface. A 1.5 kg block that is initially 0.10m above the upper end of the spring is dropped from rest onto the spring. What is the kinetic energy of the block at the instant it has fallen 0.20m ( compressing the spring 0.10m) ?


Homework Equations



1/2kxi2=Ei=mghf - energy conservation


The Attempt at a Solution



No idea. This equation above is a guess. I think it should be this one. If it is, you probably have to solve it for something, but I don't know. Solve for k ?
 
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For the second question:

You're on the right track thinking about conservation of energy. What will define the energy of the system at the moment the block is dropped? What will define the energy of the system after it has dropped and compressed the spring?
 

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