If (log x)^2 + log x^3 - 27 = log x^4 - log x^7, solve for x to 2 decimal places(adsbygoogle = window.adsbygoogle || []).push({});

(log x)^2 + log x^5 - 27 = log x^4 - log x^7

(log x)^2 + 6 log x - 27 = 0

Let log x be a

a^2 + 6a - 27 = 0

(a + 9)(a - 3) = 0

a = 3 or - 9

log x = 3 or log x = -9

... x = 10^3 or 10^-9

Please help me because i am pretty sure this answer is wrong since the question asks us to solve x to 2 decimal places. however, i don't know what mistake i made so any help is appreciated! Thanks again!

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Calculus Solving logarithmic equations

**Physics Forums | Science Articles, Homework Help, Discussion**