- #1

Shukie

- 96

- 0

## Homework Statement

I have an equation with a number of variables, of which the values and their uncertainties are known. Two of these variables are measured with a ruler, h and l. The question is, will a zero error in the ruler affect the answer or the uncertainty in the answer? The same question for a possible calibration error.

## Homework Equations

[tex]\mu = \left(\frac{\pi*R^4}{8Q}\right)*\left(\frac{p*g*(h1 - h2) - p*g*(h2 - h3)}{l1 - l2}\right)[/tex]

[tex]R = (400 \pm 4)*10^{-6} m[/tex]

[tex]Q = (100 \pm 0.5)*10^{-9} \frac{m^{3}}{s}[/tex]

[tex]l1 = (163.8 \pm 0.2)*10^{-3} m[/tex]

[tex]l2 = (101 \pm 0.2)*10^{-3} m[/tex]

[tex]h1 = (223 \pm 1)*10^{-3} m[/tex]

[tex]h2 = (83 \pm 1)*10^{-3} m[/tex]

[tex]h3 = (23 \pm 1)*10^{-3} m[/tex]

[tex]g = 10 \mbox{and} p = 1000 [/tex]

## The Attempt at a Solution

Evaluating this function I get [tex]\mu = (1.28 \pm 0.07)*10^{-3}[/tex]. The actual zero error isn't given, so I'll assume an error of 1%. Can I simply multiply all the h and l values by 1.01 and then evaluate [tex]\mu[/tex] again to see if it deviates from the above answer? If so, do I multiply the uncertainties in h and l by 1.01 as well, or only their actual values?

As for the calibration error, how is this different from the zero error?