Calorimetry Problem: Final Temp of Al+Water

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In summary, calorimetry is a method used to measure heat transfer during a chemical reaction or physical process. It involves using a calorimeter to measure the temperature change of substances before and after the reaction. The specific heat capacity of a substance affects the final temperature in a calorimetry problem as substances with higher specific heat capacities require more heat to raise their temperature. The formula used to calculate the final temperature involves the mass, specific heat capacity, and change in temperature of the substances. Common sources of error in a calorimetry experiment can be minimized by insulating the calorimeter, ensuring thorough mixing, and using precise equipment. The initial temperatures of substances do not directly affect the final temperature, but can indirectly impact the amount of heat transferred and
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Homework Statement


A 300 g piece of aluminum at a temperature of 75 degrees C is dropped into a calorimeter containing 400 mL of water at 5 degrees C. What is the final temperature? The C Al = 0.9 J/g degrees C.

Homework Equations



q = mcdeltat


The Attempt at a Solution



I have no idea where to begin o_0
 
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Heat lost = heat gained (each one is described by the equation you have listed). This will be equation with one unknown - final temperature.

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FAQ: Calorimetry Problem: Final Temp of Al+Water

1. What is calorimetry and how is it used to determine the final temperature of a system?

Calorimetry is the scientific measurement of the amount of heat absorbed or released during a chemical reaction or physical process. In the case of determining the final temperature of a system, calorimetry involves using a calorimeter, a device used to measure heat transfer, to measure the temperature change of a substance (in this case, a mixture of Al and water) before and after a reaction or process. By knowing the specific heat capacities of the substances involved, the final temperature can be calculated using the principle of heat transfer.

2. What is the specific heat capacity and how does it affect the final temperature in a calorimetry problem?

The specific heat capacity is the amount of heat required to raise the temperature of one gram of a substance by one degree Celsius. In a calorimetry problem, the specific heat capacities of the substances involved (in this case, Al and water) are used to calculate the amount of heat transferred and the resulting temperature change. A substance with a higher specific heat capacity will require more heat to raise its temperature, and therefore, will result in a smaller final temperature change compared to a substance with a lower specific heat capacity.

3. What is the formula used to calculate the final temperature in a calorimetry problem involving Al and water?

The formula used to calculate the final temperature in a calorimetry problem involving Al and water is q = m x c x ΔT, where q represents the amount of heat transferred, m represents the mass of the substance, c represents the specific heat capacity, and ΔT represents the change in temperature. In this case, the equation can be rewritten as Tfinal = (mAl x cAl x ΔTAl + mH2O x cH2O x ΔTH2O) / (mAl x cAl + mH2O x cH2O), where Tfinal represents the final temperature, and the subscripts Al and H2O refer to the aluminum and water, respectively.

4. What are the common sources of error in a calorimetry experiment and how can they be minimized?

The common sources of error in a calorimetry experiment include heat loss to the surroundings, incomplete mixing of substances, and inaccurate measurement of mass and temperature. These errors can be minimized by insulating the calorimeter, ensuring thorough mixing of substances, and using precise and calibrated equipment for mass and temperature measurements. Additionally, conducting multiple trials and taking an average can help reduce the impact of these errors on the final result.

5. How is the final temperature in a calorimetry problem affected by the initial temperatures of the substances?

The initial temperatures of the substances involved in a calorimetry problem do not directly affect the final temperature, as the change in temperature (ΔT) is the key factor in the calculation. However, the initial temperatures can indirectly affect the final temperature through their impact on the amount of heat transferred. If one substance starts at a higher temperature, it will require more heat to reach the final temperature, resulting in a smaller change in temperature for the other substance. This can affect the final temperature calculated using the formula mentioned in question 3.

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