Can a Vector Have an Expectation Value?

Click For Summary
SUMMARY

The discussion centers on the relationship between the expectation value of orbital angular momentum (L) and torque (N) for a particle in a potential V(r). It establishes that the rate of change of the expectation value of L is equal to the expectation value of N, expressed mathematically as d/dt = . The participants clarify that while vectors are not operators, their components can still possess expectation values when expressed in terms of their respective operators, leading to the equation d/dt = being valid across its components.

PREREQUISITES
  • Understanding of quantum mechanics concepts, particularly expectation values.
  • Familiarity with vector calculus and its application in physics.
  • Knowledge of operators in quantum mechanics.
  • Basic grasp of potential energy functions in quantum systems.
NEXT STEPS
  • Study the mathematical formulation of expectation values in quantum mechanics.
  • Explore the role of operators in quantum mechanics, focusing on angular momentum operators.
  • Learn about vector calculus in the context of physics, particularly in relation to torque.
  • Investigate the implications of potential energy functions on particle dynamics in quantum systems.
USEFUL FOR

Students and professionals in quantum mechanics, physicists exploring angular momentum, and anyone studying the mathematical foundations of expectation values in quantum systems.

phrygian
Messages
77
Reaction score
0

Homework Statement



Prove that for a particle in a potential V(r) the rate of change of the expectation value of the orbital angular momentum L is equal to the expectation value of the torque:

d/dt <L> = <N>

Where N = r x(-del V)

N, r, and L are vectors.

Homework Equations





The Attempt at a Solution



I know how to solve this, but do not understand the equation. How can a vector have an expectation value? A vector is not an operator, I thought only an operator can have an expectation value?

Thanks for the help
 
Physics news on Phys.org
That's three equations in one. You write out the components and the expectation value of the x component of the torque will be equal to the time derivative of the expectation value of Lx and so on.
 
In other words:

[tex]d/dt \begin{pmatrix}\langle L_x\rangle\\ \langle L_y\rangle\\ \langle L_z\rangle \end{pmatrix}= \begin{pmatrix}\langle N_x\rangle \\\langle N_y\rangle \\ \langle N_z\rangle \end{pmatrix}[/tex]

where [itex]L_x,L_y,L_z,N_x,N_y,N_z[/itex] are operators
 

Similar threads

Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
Replies
31
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
4K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K