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Aerospace Can any one explain Schuler cycle in Inertial Navigation System

  1. Dec 1, 2011 #1
    Can any one please explain schuler cycle, please don not start explaining with same old pendulum with the length of radius of earth stuff.
    why is it required ?
    what is that all about ?
  2. jcsd
  3. Dec 28, 2011 #2
    Sketch a circle and draw radii to each of two positions, true (T) and estimated (E). Let the angle between the radii be exaggerated but still narrow enough to allow small-angle approximation (sine=angle in radians).
    Since accelerometers sense the NONgravitational part of acceleration, we have to supply the gravitational part ourselves -- vectorially. So:
    Calling the chord distance "x" the radius "r" and gravity "g" note that
    * the true gravity vector is vertical (down along the radius
    from "T")
    * the apparent gravity vector (down along the radius from
    "E") has a small projection along the chord from "T" to "E"
    producing a horizontal error in acceleration, OPPOSITE the
    direction of position error.

    By the small-angle approximation and the opposite sign, the acceleration error is then
    (-x/r) g = (-g/r) x
    i.e., the second time derivative of "x" equals (-g/r) times "x" -- that's the differential equation of a sinusoid. Plug in numbers for Earth radius and gravity -- you'll get an amount in radian/sec corresponding to a period between 83 and 84 minutes.
    There's a little more to it but that explains the basics. For more info I'll cite a tutorial at http://www.ion.org/tutorials/ [Broken]

    << additional book reference deleted by Mentor >>
    Last edited by a moderator: May 5, 2017
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