Amer
- 259
- 0
how to prove that for any real number in r (0,1) there exist a natural number n in N such that
rn > 1
rn > 1
Amer said:how to prove that for any real number in r (0,1) there exist a natural number n in N such that
rn > 1
I don't understand the question. What is "r (0,1)"? You want a number n such that m > 1? If you want a number > 1, why not take 2?Amer said:how to prove that for any real number in r (0,1) there exist a natural number n in N such that
rn > 1
Evgeny.Makarov said:I don't understand the question. What is "r (0,1)"? You want a number n such that m > 1? If you want a number > 1, why not take 2?
Prove that for any real number \(r \in (0,1)\) there exist a natural number \(n \in N\) such that \(r n > 1\)
Wow, talk about keming. It is true, I recently changed contact lenses and my vision went down a bit.CaptainBlack said:What you have taken to be an "m" is in fact "r n" but with no space so that in the default font it looks like m