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Can anybody help me to find acceleration

  • Thread starter rashida564
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  • #1
rashida564
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< Mentor Note -- poster has been reminded to use the Homework Help Template and show their work next time >

what is the acceleration for this equation Δx=4.0t+3.0t2
and thank you a lot
 
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  • #2
cnh1995
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what is the acceleration for this equation Δx=4.0t+3.0t2
and thank you a lot
Please use proper homework template and show your attempt. It is mandatory when posting on homework help forums.
 
  • #3
rashida564
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and i also think the acceleration is equal to 6 m/s2
 
  • #5
rashida564
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98144321cea7a6732948ffbb803ccdd9970fa29ca2e4d6f4fe4513f848b27349dc6e249c.jpg
 
  • #6
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So, are you able to articulate your question?
 
  • #7
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One hint
What if you made the time interval infinitesimally small?
Wouldn't v=delta x/delta t (t tends to 0) become dx/dt
Do the same thing with the velocity
You should be able to get a=d^2x/dt^2
And yes you get v=4+6t
And a =dv/dt=6
Your answer is correct






UchihaClan13
 
  • #8
rashida564
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  • #9
rashida564
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but can you me without calculus
 
  • #10
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but can you me without calculus
If v0 is the initial velocity (at time 0) and a is a constant acceleration, the velocity v at time t is ##v=v_0+at##. The average velocity between time 0 and time t is $$v_{ave}=\frac{v_0+v}{2}=v_0+\frac{1}{2}at$$The distance traveled is equal to the average velocity times the time:
$$x=v_{ave}t=v_0t+\frac{1}{2}at^2$$
 
  • #11
rashida564
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then i should do that
1/2a=3
a=6
 
  • #12
19,941
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then i should do that
1/2a=3
a=6
Yes. You were asking for a non-calculus derivation, so this is it.
 
  • #13
rashida564
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thank you
 

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