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Can anybody help me to find acceleration

  1. Apr 15, 2016 #1
    < Mentor Note -- poster has been reminded to use the Homework Help Template and show their work next time >

    what is the acceleration for this equation Δx=4.0t+3.0t2
    and thank you a lot
     
    Last edited by a moderator: Apr 15, 2016
  2. jcsd
  3. Apr 15, 2016 #2

    cnh1995

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    Homework Helper

    Please use proper homework template and show your attempt. It is mandatory when posting on homework help forums.
     
  4. Apr 15, 2016 #3
    and i also think the acceleration is equal to 6 m/s2
     
  5. Apr 15, 2016 #4
  6. Apr 15, 2016 #5
    98144321cea7a6732948ffbb803ccdd9970fa29ca2e4d6f4fe4513f848b27349dc6e249c.jpg
     
  7. Apr 15, 2016 #6
    So, are you able to articulate your question?
     
  8. Apr 15, 2016 #7
    One hint
    What if you made the time interval infinitesimally small?
    Wouldn't v=delta x/delta t (t tends to 0) become dx/dt
    Do the same thing with the velocity
    You should be able to get a=d^2x/dt^2
    And yes you get v=4+6t
    And a =dv/dt=6
    Your answer is correct






    UchihaClan13
     
  9. Apr 15, 2016 #8
  10. Apr 15, 2016 #9
    but can you me without calculus
     
  11. Apr 15, 2016 #10
    If v0 is the initial velocity (at time 0) and a is a constant acceleration, the velocity v at time t is ##v=v_0+at##. The average velocity between time 0 and time t is $$v_{ave}=\frac{v_0+v}{2}=v_0+\frac{1}{2}at$$The distance traveled is equal to the average velocity times the time:
    $$x=v_{ave}t=v_0t+\frac{1}{2}at^2$$
     
  12. Apr 16, 2016 #11
    then i should do that
    1/2a=3
    a=6
     
  13. Apr 16, 2016 #12
    Yes. You were asking for a non-calculus derivation, so this is it.
     
  14. Apr 16, 2016 #13
    thank you
     
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