Can anyone confirm this possible error in 'Vector Calculus' by Matthews?

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SUMMARY

The discussion centers on the surface integral of the vector field u = (2y+x,-1,0) over the surface defined by z = x + y², specifically for z<0 and x>-1. A key point of contention is the treatment of the unit normal vector n, which is derived from the parameterized surface r = (x,y,x+y²). The solution provided in the text claims ndS = (1,2y,-1)dxdy, which raises questions about whether n is appropriately normalized. The correct approach involves calculating the cross product of the partial derivatives of r and normalizing it by its magnitude, √(2 + 4y²).

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Syrus
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Homework Statement



Find the surface integral of u dot n over S where S is the part of the surface z = x + y2 with z<0 and x>-1, u is the vector field u = (2y+x,-1,0) and n has a negative z component.

Homework Equations



In the text leading up to the end-of-chapter exercises (where this question arises), n is specified as a unit normal vector.

The Attempt at a Solution



The solution claims that ndS = (1,2y,-1)dxdy. But isn't this ignoring the fact that n should be a unit vector? Obviously, the position vector for the surface in parameter form is r = (x,y,x+y2), and n is obtained by taking the partial derivative of r with respect to y, the partial derivative of r with respect to x, and forming the cross product of the two (in that order). But then, shouldn't this resulting vector be divided by the magnitude of the cross product- which, by my calculations happens to be √(2 + 4y2), which is never 1?
 
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Syrus said:

Homework Statement



Find the surface integral of u dot n over S where S is the part of the surface z = x + y2 with z<0 and x>-1, u is the vector field u = (2y+x,-1,0) and n has a negative z component.



Homework Equations



In the text leading up to the end-of-chapter exercises (where this question arises), n is specified as a unit normal vector.

The Attempt at a Solution



The solution claims that ndS = (1,2y,-1)dxdy. But isn't this ignoring the fact that n should be a unit vector? Obviously, the position vector for the surface in parameter form is r = (x,y,x+y2), and n is obtained by taking the partial derivative of r with respect to y, the partial derivative of r with respect to x, and forming the cross product of the two (in that order). But then, shouldn't this resulting vector be divided by the magnitude of the cross product- which, by my calculations happens to be √(2 + 4y2), which is never 1?

Your surface is parameterized as ##\vec R(x,y) = \langle x, y, x+y^2\rangle##. Read my post #13 in this thread:

https://www.physicsforums.com/showthread.php?t=611873

with u = x and v = y and you will see why the book is correct.
 
Understood. Thank you, LCKurtz.
 

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